- \(\displaystyle \int x^p\,dx= \frac{x^{p+1}}{p+1}+C\), for \(p\neq -1\)
- \(\displaystyle \int \frac1x\,dx= \ln\left|x\right|+C\)
- \(\displaystyle\int e^x\,dx= e^x+C\)
- \(\displaystyle\int a^x\,dx= \frac{a^x}{\ln a}+C\), for \(a > 0\) and \(a\neq 1\)
- \(\displaystyle\int \ln x\,dx=x\ln x-x+C\)
- \(\displaystyle\int \cos x\,dx=\sin x+C\)
- \(\displaystyle\int \sin x\,dx=-\cos x+C\)
- \(\displaystyle \int \frac1{\cos^2x}\,dx=\tan x+C\)
- \(\displaystyle \int \frac1{\sin^2x}\,dx=-\cot x+C\)
- \(\displaystyle \int \sec x\cdot \tan x\,dx=\sec x+C\)
- \(\displaystyle \int\tan x\,dx=-\ln\left|\cos x\right|+C\)
- \(\displaystyle \int\cot x\,dx=\ln\left|\sin x\right|+C\)
- \(\displaystyle \int \arcsin x\,dx=x\arcsin x+\sqrt{1-x^2}+C\)
- \(\displaystyle \int \arctan x\,dx=x\arctan x-\frac12\ln\left(1+x^2\right)+C\)
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\[ \quad\]
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- \(\displaystyle \int e^{ax}\sin(bx)\,dx =\frac{e^{ax}\left(a\sin(bx)-b\cos(bx)\right)}{a^2+b^2}+C\)
- \(\displaystyle \int e^{ax}\cos(bx)\,dx=\frac{e^{ax}\left(a\cos(bx)+b\sin(bx)\right)}{a^2+b^2}+C\)
- \(\displaystyle \int \frac{dx}{x^2+a^2}=\frac1a\arctan\frac{x}{a}+C\)
- \(\displaystyle \int \frac{dx}{x^2-a^2}=\frac1{2a}\ln\left|\frac{x-a}{x+a}\right|+C\)
- \(\displaystyle \int \frac{dx}{\sqrt{a^2-x^2}}=\arcsin \frac{x}{a}+C\)
- \(\displaystyle \int\frac{dx}{\sqrt{x^2\pm a^2}}=\ln\left|x+\sqrt{x^2\pm a^2}\right|+C\)
- \(\displaystyle \int\frac{dx}{\sqrt{x^2\pm a^2}^3}=\pm\frac{x}{a^2\sqrt{x^2\pm a^2}}+C\)
- \(\displaystyle \int \sqrt{x^2\pm a^2}\,dx=\pm\frac{a^2}2\ln\left|x +\sqrt{x^2\pm a^2}\right|\) \(\displaystyle+\frac{x}2\sqrt{x^2\pm a^2}+C\)
- \(\displaystyle \int \sqrt{x^2\pm a^2}^3\,dx=\frac{x}8\left(2x^2\pm5a^2\right)\sqrt{x^2\pm a^2}\) \(\displaystyle+\frac{3a^4}8\ln\left|x+\sqrt{x^2\pm a^2}\right|+ C\)
- \(\displaystyle \int_{-\infty}^{+\infty}e^{-x^2}\,dx=\sqrt{\pi}\)
- \(\displaystyle \int_0^{+\infty}\frac{\sin x}x\,dx=\frac{\pi}2\)
- \(\displaystyle \int_0^{\frac{\pi}2}\sin^{2n}x\,dx=\frac{(2n-1)!!}{(2n)!!}\cdot\frac{\pi}2\), for \(n\in\mathbb N\cup\{0\}\)
- \(\displaystyle \int_0^{\frac{\pi}2}\sin^{2n+1}x\,dx=\frac{(2n)!!}{(2n+1)!!}\), for \(n\in\mathbb N\cup \{0\}\)
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