Antiderivatives and Indefinite Integrals
Definition
Definition (Antiderivative)
A function \(F\) is an antiderivative of a function \(f\) on the interval \((a,b)\) if \(F^{\prime}(x)=f(x)\) for every \(x\in(a,b)\).
The function \(f(x)=3x^2\) has many anti-derivatives: \(F_1(x)=x^3\), \(F_2(x)=x^3-17\), \(F_3(x)=x^3+41\), etc. They all differ by a constant factor.
Definition (Indefinite integral)
The set of all antiderivatives of a given function \(f\) is called the indefinite integral of \(f\), and it is denoted as \(\int f(x)\,dx\). More precisely \[\int f(x)\,dx=\left\{ F: F^{\prime}(x)=f(x)\right\}.\]
Consider the function \(f(x)=\cos x\). For each real number \(C\), the function \(F_C(x)=\sin x+C\) is an antiderivative of \(f\). We write \[\int \cos x\,dx=\sin x+C.\]
Main properties of indefinite integrals
Theorem
If \(F_1\) and \(F_2\) are two antiderivatives of \(f\) then there exists a real number \(C\) such that \(F_1(x)-F_2(x)=C\) for all \(x\).
The function \(g(x)=F_1(x)-F_2(x)\) satisfies \(g^{\prime}(x)=0\) for all \(x\). Therefore \(g\) must be a constant function.
The following theorem is easy to prove using the main properties of derivatives.
Theorem
For any function \(f\) and any real number \(\alpha\) the following identity holds: \[\int \alpha \cdot f(x)\,dx=\alpha\int f(x)\,dx.\]
For any two functions \(f\) and \(g\) the following identity holds: \[\int (f+g)(x)\,dx=\int f(x)\,dx+\int g(x)\,dx.\]
We can use the previous theorem to find anti-derivatives of polynomials. For example, if \(P(x)=x^3-2x^2+11x+4\), then \[\int P(x)\,dx=\int x^3\,dx-2\int x^2\,dx+11\int x\,dx+4\int 1\,dx=
\frac14x^3-2\frac{x^3}3+11\frac{x^2}2+4x+C,\] where \(C\) could be any real number.
Practice problems
Problem 1. Let \[F(x)=\cos^2 x-\sin^2 x,\] \[G(x)=2\cos^2x,\] \[H(x)=2\sin^2x,\] \[K(x)=\cos (2x).\]
Which of the previously defined functions are anti-derivatives of the function \[\varphi(x)=-4\sin x\cdot\cos x.\]
- (A) \(F\) only
- (B) \(F\) and \(K\) only
- (C) \(F\), \(G\), and \(K\) only
- (D) \(H\) and \(K\) only
- (E) \(H\) only
It is easy to verify that \(F^{\prime}(x)=G^{\prime}(x)=K^{\prime}(x)=-2\sin x\cdot \cos x=\varphi(x)\). The derivative of \(H\) is \(H'(x)=-4\sin x\cos x\). Hence, the answer is C.
Problem 2. Determine \[\int \left(x^3-3\cos x\right)\,dx.\]
We use the basic properties of the indefinite integral to obtain:
\[\int \left(x^3-3\cos x\right)\,dx=\int x^3\,dx-3\int \cos x\,dx=\frac{x^4}4-3\sin x+C.\]
Problem 3. Determine \[\int\frac1{\cos^2x}\,dx.\]
- (A) \(\ln(\cos x)\)
- (B) \(\ln(\cos x)+C\)
- (C) \(\ln(\cos x + C)\)
- (D) \(\tan x\)
- (E) \(\tan x+C\)
Direct verification shows that the answer is E.
Problem 4. Assume that \(p\) is a real number different from \(-1\). Find \[\int x^p\,dx.\]
- (A) \(\frac1{p+1}x^{p+1}\)
- (B) \(px^{p-1}\)
- (C) \(0\)
- (D) \(\frac1{p+1}x^{p+1}+C\)
- (E) \(px^{p-1}+C\)
Direct verification shows that the derivative of \(F(x)=\frac1{p+1}x^{p+1}+C\) is equal to \(x^p\). The correct answer is \(D\).
Problem 5. Determine \[\int\frac1{x^2+1}\,dx.\]
- (A) \(\arctan x+C\)
- (B) \(\arctan x\)
- (C) \(\ln(1+x^2)+C\)
- (D) \(\ln(1+x^2)\)
- (E) \(x\ln (1+x^2)\)
Direct verification shows that the answer is A.